Talk:Counting House

The Multiplayer section says "you end up with a 9:6:5 curse split".

That seems peculiar to me, so perhaps I'm missing something.

Isn't 10:6:4 or 10:5:5 far more likely?

Above contribution from ‎70.36.235.51

I can't see how to get 9:6:5 either. Twenty curse cards will be issues afer 20 curse cards have been played if there is no blocking you get hit each time. That means CH player gets 10. The other 10 split between the other two depending on the usual chance. --Cammuppet (talk) 07:27, 27 June 2014 (EDT)