Talk:Counting House
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I can't see how to get 9:6:5 either. Twenty curse cards will be issues afer 20 curse cards have been played if there is no blocking you get hit each time. That means CH player gets 10. The other 10 split between the other two depending on the usual chance. --[[User:Cammuppet|Cammuppet]] ([[User talk:Cammuppet|talk]]) 07:27, 27 June 2014 (EDT) | I can't see how to get 9:6:5 either. Twenty curse cards will be issues afer 20 curse cards have been played if there is no blocking you get hit each time. That means CH player gets 10. The other 10 split between the other two depending on the usual chance. --[[User:Cammuppet|Cammuppet]] ([[User talk:Cammuppet|talk]]) 07:27, 27 June 2014 (EDT) | ||
| + | == 404 == | ||
| + | All games have a 404 error. anyone want to fix it? [[Special:Contributions/74.102.70.142|74.102.70.142]] 14:18, 7 August 2015 (EDT) | ||
Revision as of 14:18, 7 August 2015
The Multiplayer section says "you end up with a 9:6:5 curse split".
That seems peculiar to me, so perhaps I'm missing something.
Isn't 10:6:4 or 10:5:5 far more likely?
Above contribution from 70.36.235.51
I can't see how to get 9:6:5 either. Twenty curse cards will be issues afer 20 curse cards have been played if there is no blocking you get hit each time. That means CH player gets 10. The other 10 split between the other two depending on the usual chance. --Cammuppet (talk) 07:27, 27 June 2014 (EDT)
404
All games have a 404 error. anyone want to fix it? 74.102.70.142 14:18, 7 August 2015 (EDT)
